Introduction to quartile example:
The median calculate the central point of a distribution, bottom on the order, just about half of the information set falls under the median and half falls over the median. The middle of the division is successful method to use. For the median, a usual measure of spreading can obtain from the lesser and higher quartile. The quartile contains the upper quartile and also the lower quartile. Let us see about the topic to quartile(upper quartile and lower quartile) example help are given below in the contents.
Example Problems to Solve the Method Quartile Example
let us see about the topic quartile example we can see bout different method to solve quartile (upper, lower, meadian and interquartile and range),
Example problem1:-using solve the method quartile example
Calculate the meadian, lesser quartile, higher quartile, interquartile and range of the given information of the following sequence.
15, 50, 31, 40, 18, 13, 24, 19, 25, 45, 12, 20.
Solution:
Initial, arrange the data in ascending order:
Given: 12, 13, 15, 18, 19, 20, 24, 25, 31, 40, 45, 50
Step :1
12, 13, 15 ,18, 19, 20,| 24, 25, 31, 40,45, 50
Lower quartile Median Upper quartile
Step :2 Find the meadian for lower quartile
Lower quartile = `(15+33)/2` = 16.5
Step :3
Median = `(20+24)/2` = 22
Step :4 Find the meadian for upper quartile
Upper quartile = `(31+40)/2` = 35.5
Step: 5
Interquartile range = Upper quartile – lower quartile
= 35.5 – 16.5 = 19
Step: 6
Range = largest value – smallest value
= 50 – 12 = 38
Please express your views of this topic solving two step linear equations by commenting on blog.
Example Problem2:-using to Solve the Method Quartile Example
Estimate the median, lower quartile, upper quartile, interquartile and range of the given information of the following sequence.
15, 45, 35, 25, 65, 12, 30, 9, 20, 55, 95, 70.
Solution:
Initial, arrange the data in ascending order:
Given data: 9, 12, 15, 20, 25, 30, 35, 45, 55, 65, 70, 95
Step: 1
9, 12, 15, 20, 25, 30, | 35, 45, 55, 65, 70, 95
Lower quartile Median Upper quartile
Step :2 Find the meadian for lower quartile
Lower quartile = `(15 +20)/2` =17.5
Step :3
Median = `(30+35)/2` = 32.5
Step :4 Find the meadian for upper quartile
Upper quartile = `(55+65)/2` = 60
Step :5
Interquartile range = Upper quartile – lower quartile
= 60 – 17.5 = 77.5
Step :6
Range = largest value – smallest value
= 95 – 5 = 90
The median calculate the central point of a distribution, bottom on the order, just about half of the information set falls under the median and half falls over the median. The middle of the division is successful method to use. For the median, a usual measure of spreading can obtain from the lesser and higher quartile. The quartile contains the upper quartile and also the lower quartile. Let us see about the topic to quartile(upper quartile and lower quartile) example help are given below in the contents.
Example Problems to Solve the Method Quartile Example
let us see about the topic quartile example we can see bout different method to solve quartile (upper, lower, meadian and interquartile and range),
Example problem1:-using solve the method quartile example
Calculate the meadian, lesser quartile, higher quartile, interquartile and range of the given information of the following sequence.
15, 50, 31, 40, 18, 13, 24, 19, 25, 45, 12, 20.
Solution:
Initial, arrange the data in ascending order:
Given: 12, 13, 15, 18, 19, 20, 24, 25, 31, 40, 45, 50
Step :1
12, 13, 15 ,18, 19, 20,| 24, 25, 31, 40,45, 50
Lower quartile Median Upper quartile
Step :2 Find the meadian for lower quartile
Lower quartile = `(15+33)/2` = 16.5
Step :3
Median = `(20+24)/2` = 22
Step :4 Find the meadian for upper quartile
Upper quartile = `(31+40)/2` = 35.5
Step: 5
Interquartile range = Upper quartile – lower quartile
= 35.5 – 16.5 = 19
Step: 6
Range = largest value – smallest value
= 50 – 12 = 38
Please express your views of this topic solving two step linear equations by commenting on blog.
Example Problem2:-using to Solve the Method Quartile Example
Estimate the median, lower quartile, upper quartile, interquartile and range of the given information of the following sequence.
15, 45, 35, 25, 65, 12, 30, 9, 20, 55, 95, 70.
Solution:
Initial, arrange the data in ascending order:
Given data: 9, 12, 15, 20, 25, 30, 35, 45, 55, 65, 70, 95
Step: 1
9, 12, 15, 20, 25, 30, | 35, 45, 55, 65, 70, 95
Lower quartile Median Upper quartile
Step :2 Find the meadian for lower quartile
Lower quartile = `(15 +20)/2` =17.5
Step :3
Median = `(30+35)/2` = 32.5
Step :4 Find the meadian for upper quartile
Upper quartile = `(55+65)/2` = 60
Step :5
Interquartile range = Upper quartile – lower quartile
= 60 – 17.5 = 77.5
Step :6
Range = largest value – smallest value
= 95 – 5 = 90
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