Friday, November 23, 2012

Quartile Example

Introduction to quartile example:

The median calculate the central point of a distribution, bottom on the order, just about half of the information set falls under the median and half falls over the median.  The middle of the division is successful method to use. For the median, a usual measure of spreading can obtain from the lesser and higher quartile. The quartile contains the upper quartile and also the lower quartile. Let us see about the topic to quartile(upper quartile and lower quartile) example help are given below in the contents.

Example Problems to Solve the Method Quartile Example

let us see about the topic quartile example we can see bout different method to solve quartile (upper, lower, meadian and interquartile and range),

Example problem1:-using solve the method quartile example

Calculate the meadian, lesser quartile, higher quartile, interquartile and range of the given information of the following sequence.

15, 50, 31, 40, 18, 13, 24, 19, 25, 45, 12, 20.

Solution:

Initial, arrange the data in ascending order:

Given:  12, 13, 15, 18, 19, 20, 24, 25, 31, 40, 45, 50

Step :1

12, 13, 15 ,18,  19,  20,| 24, 25,  31, 40,45, 50

Lower quartile       Median         Upper quartile

Step :2 Find the meadian for lower quartile

Lower quartile = `(15+33)/2` = 16.5

Step :3

Median = `(20+24)/2` = 22

Step :4 Find the meadian for upper quartile

Upper quartile = `(31+40)/2` = 35.5

Step: 5

Interquartile range = Upper quartile – lower quartile

= 35.5 – 16.5 = 19

Step: 6

Range = largest value – smallest value

= 50 – 12 = 38

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Example Problem2:-using to Solve the Method Quartile Example

Estimate the median, lower quartile, upper quartile, interquartile and range of the given information of the following sequence.

15, 45, 35, 25, 65, 12, 30, 9, 20, 55, 95, 70.

Solution:

Initial, arrange the data in ascending order:

Given data:  9, 12, 15, 20, 25, 30, 35, 45, 55, 65, 70, 95

Step: 1

9, 12, 15, 20, 25, 30, | 35, 45, 55, 65, 70, 95

Lower quartile       Median              Upper quartile

Step :2 Find the meadian for lower quartile

Lower quartile = `(15 +20)/2` =17.5

Step :3

Median = `(30+35)/2` = 32.5

Step :4 Find the meadian for upper quartile

Upper quartile = `(55+65)/2` = 60

Step :5

Interquartile range = Upper quartile – lower quartile

= 60 – 17.5 = 77.5

Step :6

Range = largest value – smallest value

= 95 – 5 = 90

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